Programming

Java로 맵을 인쇄하십시오

procodes 2020. 7. 1. 22:19
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Java로 맵을 인쇄하십시오


를 인쇄하는 좋은 방법을 찾고 있습니다 Map.

map.toString() 나에게 준다 : {key1=value1, key2=value2, key3=value3}

내 맵 항목 값에서 더 많은 자유를 원하고 다음과 같은 것을 찾고 있습니다. key1="value1", key2="value2", key3="value3"

나는이 작은 코드를 썼다 :

StringBuilder sb = new StringBuilder();
Iterator<Entry<String, String>> iter = map.entrySet().iterator();
while (iter.hasNext()) {
    Entry<String, String> entry = iter.next();
    sb.append(entry.getKey());
    sb.append('=').append('"');
    sb.append(entry.getValue());
    sb.append('"');
    if (iter.hasNext()) {
        sb.append(',').append(' ');
    }
}
return sb.toString();

그러나 나는 이것을하기 위해보다 우아하고 간결한 방법이 있다고 확신합니다.


또는 당신의 논리를 깔끔하고 작은 수업에 넣으십시오.

public class PrettyPrintingMap<K, V> {
    private Map<K, V> map;

    public PrettyPrintingMap(Map<K, V> map) {
        this.map = map;
    }

    public String toString() {
        StringBuilder sb = new StringBuilder();
        Iterator<Entry<K, V>> iter = map.entrySet().iterator();
        while (iter.hasNext()) {
            Entry<K, V> entry = iter.next();
            sb.append(entry.getKey());
            sb.append('=').append('"');
            sb.append(entry.getValue());
            sb.append('"');
            if (iter.hasNext()) {
                sb.append(',').append(' ');
            }
        }
        return sb.toString();

    }
}

용법:

Map<String, String> myMap = new HashMap<String, String>();

System.out.println(new PrettyPrintingMap<String, String>(myMap));

참고 : 해당 논리를 유틸리티 메소드에 넣을 수도 있습니다.


Arrays.toString(map.entrySet().toArray())

구아바 도서관을 살펴보십시오.

Joiner.MapJoiner mapJoiner = Joiner.on(",").withKeyValueSeparator("=");
System.out.println(mapJoiner.join(map));

구조에 아파치 라이브러리!

MapUtils.debugPrint(System.out, "myMap", map);

필요한 모든 Apache Commons Collections 라이브러리 ( 프로젝트 링크 )

Maven 사용자는이 종속성을 사용하여 라이브러리를 추가 할 수 있습니다.

<dependency>
    <groupId>commons-collections</groupId>
    <artifactId>commons-collections</artifactId>
    <version>3.2.1</version>
</dependency>

간단하고 쉽습니다. JSON 세계에 오신 것을 환영합니다. 사용 구글의 GSON를 :

new Gson().toJson(map)

키가 3 개인지도의 예 :

{"array":[null,"Some string"],"just string":"Yo","number":999}

org.json.JSONObject클래스 패스에 있을 때 나는 :

Map<String, Object> stats = ...;
System.out.println(new JSONObject(stats).toString(2));

(this beautifully indents lists, sets and maps which may be nested)


Using Java 8 Streams:

Map<Object, Object> map = new HashMap<>();

String content = map.entrySet()
                    .stream()
                    .map(e -> e.getKey() + "=\"" + e.getValue() + "\"")
                    .collect(Collectors.joining(", "));

System.out.println(content);

I prefer to convert the map to a JSON string it is:

  • a standard
  • human readable
  • supported in editors like Sublime, VS Code, with syntax highlighting, formatting and section hide/show
  • supports JPath so editors can report exactly which part of the object you have navigated to
  • supports nested complex types within the object

    import com.fasterxml.jackson.core.JsonProcessingException;
    import com.fasterxml.jackson.databind.ObjectMapper;
    
    public static String getAsFormattedJsonString(Object object)
    {
        ObjectMapper mapper = new ObjectMapper();
        try
        {
            return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(object);
        }
        catch (JsonProcessingException e)
        {
            e.printStackTrace();
        }
        return "";
    }
    

Look at the code for HashMap#toString() and AbstractMap#toString() in the OpenJDK sources:

class java.util.HashMap.Entry<K,V> implements Map.Entry<K,V> {
       public final String toString() {
           return getKey() + "=" + getValue();
       }
   }
 class java.util.AbstractMap<K,V> {
     public String toString() {
         Iterator<Entry<K,V>> i = entrySet().iterator();
         if (! i.hasNext())
            return "{}";

        StringBuilder sb = new StringBuilder();
        sb.append('{');
        for (;;) {
            Entry<K,V> e = i.next();
            K key = e.getKey();
            V value = e.getValue();
            sb.append(key   == this ? "(this Map)" : key);
            sb.append('=');
            sb.append(value == this ? "(this Map)" : value);
            if (! i.hasNext())
                return sb.append('}').toString();
            sb.append(", ");
        }
    }
}

So if the guys from OpenJDK did not find a more elegant way to do this, there is none :-)


You should be able to do what you want by doing:

System.out.println(map) for example

As long as ALL your objects in the map have overiden the toString method you would see:
{key1=value1, key2=value2} in a meaningfull manner

If this is for your code, then overiding toString is a good habit and I suggest you go for that instead.

For your example where your objects are Strings you should be fine without anything else.
I.e. System.out.println(map) would print exactly what you need without any extra code


public void printMapV2 (Map <?, ?> map) {
    StringBuilder sb = new StringBuilder(128);
    sb.append("{");
    for (Map.Entry<?,?> entry : map.entrySet()) {
        if (sb.length()>1) {
            sb.append(", ");
        }
        sb.append(entry.getKey()).append("=").append(entry.getValue());
    }
    sb.append("}");
    System.out.println(sb);
}

I guess something like this would be cleaner, and provide you with more flexibility with the output format (simply change template):

    String template = "%s=\"%s\",";
    StringBuilder sb = new StringBuilder();
    for (Entry e : map.entrySet()) {
        sb.append(String.format(template, e.getKey(), e.getValue()));
    }
    if (sb.length() > 0) {
        sb.deleteCharAt(sb.length() - 1); // Ugly way to remove the last comma
    }
    return sb.toString();

I know having to remove the last comma is ugly, but I think it's cleaner than alternatives like the one in this solution or manually using an iterator.


As a quick and dirty solution leveraging existing infrastructure, you can wrap your uglyPrintedMap into a java.util.HashMap, then use toString().

uglyPrintedMap.toString(); // ugly
System.out.println( uglyPrintedMap ); // prints in an ugly manner

new HashMap<Object, Object>(jobDataMap).toString(); // pretty
System.out.println( new HashMap<Object, Object>(uglyPrintedMap) ); // prints in a pretty manner

Does not answer exactly the question, but it is worth mentioning Lombodok @ToString annotation. If you annotate with @ToString the key / value classes, then doing System.out.println(map) will return something meaningful.

It also works very well with maps-of-maps, for example: Map<MyKeyClass, Map<String, MyValueClass>> will be printed as

{MyKeyClass(properties...)={string1=MyValuesClass(properties...), string2=MyValuesCalss(properties...),..}, ... }


String result = objectMapper.writeValueAsString(map) - as simple as this!

Result:

{"2019-07-04T03:00":1,"2019-07-04T04:00":1,"2019-07-04T01:00":1,"2019-07-04T02:00":1,"2019-07-04T13:00":1,"2019-07-04T06:00":1 ...}

P.S. add Jackson JSON to your classpath.

참고URL : https://stackoverflow.com/questions/10120273/pretty-print-a-map-in-java

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