Java의 표준 입력에서 정수 값을 읽는 방법

Java의 표준 입력에서 정수 값을 읽는 방법

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Java에서 정수 변수를 읽는 데 어떤 클래스를 사용할 수 있습니까?

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java.util.Scanner( API )를 사용할 수 있습니다 .

import java.util.Scanner;

//...

Scanner in = new Scanner(System.in);
int num = in.nextInt();

또한 정규식 등으로 입력을 토큰화할 수 있습니다. API에는 예제가 있으며이 사이트에는 다른 많은 예제가 있습니다 (예 : 잘못된 유형이 입력 될 때 스캐너가 예외를 발생시키지 않도록하려면 어떻게해야합니까? ).

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Java 6을 사용하는 경우 다음 oneliner를 사용하여 콘솔에서 정수를 읽을 수 있습니다.

int n = Integer.parseInt(System.console().readLine());

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여기에서는 표준 입력에서 정수 값을 읽는 두 가지 예를 제공합니다.

예 1

import java.util.Scanner;
public class Maxof2
{ 
  public static void main(String args[])
  {
       //taking value as command line argument.
        Scanner in = new Scanner(System.in); 
       System.out.printf("Enter i Value:  ");
       int i = in.nextInt();
       System.out.printf("Enter j Value:  ");
       int j = in.nextInt();
       if(i > j)
           System.out.println(i+"i is greater than "+j);
       else
           System.out.println(j+" is greater than "+i);
   }
 }

예 2

public class ReadandWritewhateveryoutype
{ 
  public static void main(String args[]) throws java.lang.Exception
  {
System.out.printf("This Program is used to Read and Write what ever you type \nType  quit  to Exit at any Moment\n\n");
    java.io.BufferedReader r = new java.io.BufferedReader (new java.io.InputStreamReader (System.in));
     String hi;
     while (!(hi=r.readLine()).startsWith("quit"))System.out.printf("\nYou have typed: %s \n",hi);
     }
 }

저는 첫 번째 예를 선호합니다. 쉽고 이해하기 쉽습니다.
다음 웹 사이트에서 온라인으로 JAVA 프로그램을 컴파일하고 실행할 수 있습니다. http://ideone.com

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이것을 확인하십시오 :

public static void main(String[] args) {
    String input = null;
    int number = 0;
    try {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        input = bufferedReader.readLine();
        number = Integer.parseInt(input);
    } catch (NumberFormatException ex) {
       System.out.println("Not a number !");
    } catch (IOException e) {
        e.printStackTrace();
    }
}

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위의 두 번째 대답은 가장 간단한 대답입니다.

int n = Integer.parseInt(System.console().readLine());

The question is "How to read from standard input".

A console is a device typically associated to the keyboard and display from which a program is launched.

You may wish to test if no Java console device is available, e.g. Java VM not started from a command line or the standard input and output streams are redirected.

Console cons;
if ((cons = System.console()) == null) {
    System.err.println("Unable to obtain console");
    ...
}

Using console is a simple way to input numbers. Combined with parseInt()/Double() etc.

s = cons.readLine("Enter a int: ");
int i = Integer.parseInt(s);    

s = cons.readLine("Enter a double: ");
double d = Double.parseDouble(s);

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check this one:

import java.io.*;
public class UserInputInteger
{
        public static void main(String args[])throws IOException
        {
        InputStreamReader read = new InputStreamReader(System.in);
        BufferedReader in = new BufferedReader(read);
        int number;
                System.out.println("Enter the number");
                number = Integer.parseInt(in.readLine());
    }
}

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This causes headaches so I updated a solution that will run using the most common hardware and software tools available to users in December 2014. Please note that the JDK/SDK/JRE/Netbeans and their subsequent classes, template libraries compilers, editors and debuggerz are free.

This program was tested with Java v8 u25. It was written and built using
Netbeans IDE 8.0.2, JDK 1.8, OS is win8.1 (apologies) and browser is Chrome (double-apologies) - meant to assist UNIX-cmd-line OG's deal with modern GUI-Web-based IDEs at ZERO COST - because information (and IDEs) should always be free. By Tapper7. For Everyone.

code block:

    package modchk; //Netbeans requirement.
    import java.util.Scanner;
    //import java.io.*; is not needed Netbeans automatically includes it.           
    public class Modchk {
        public static void main(String[] args){
            int input1;
            int input2;

            //Explicity define the purpose of the .exe to user:
            System.out.println("Modchk by Tapper7. Tests IOStream and basic bool modulo fxn.\n"
            + "Commented and coded for C/C++ programmers new to Java\n");

            //create an object that reads integers:
            Scanner Cin = new Scanner(System.in); 

            //the following will throw() if you don't do you what it tells you or if 
            //int entered == ArrayIndex-out-of-bounds for your system. +-~2.1e9
            System.out.println("Enter an integer wiseguy: ");
            input1 = Cin.nextInt(); //this command emulates "cin >> input1;"

            //I test like Ernie Banks played hardball: "Let's play two!"
            System.out.println("Enter another integer...anyday now: ");
            input2 = Cin.nextInt(); 

            //debug the scanner and istream:
            System.out.println("the 1st N entered by the user was " + input1);
            System.out.println("the 2nd N entered by the user was " + input2);

            //"do maths" on vars to make sure they are of use to me:
            System.out.println("modchk for " + input1);
            if(2 % input1 == 0){
                System.out.print(input1 + " is even\n"); //<---same output effect as *.println
                }else{
                System.out.println(input1 + " is odd");
            }//endif input1

            //one mo' 'gain (as in istream dbg chk above)
            System.out.println("modchk for " + input2);
            if(2 % input2 == 0){
                System.out.print(input2 + " is even\n");
                }else{
                System.out.println(input2 + " is odd");
            }//endif input2
        }//end main
    }//end Modchk

참고URL : https://stackoverflow.com/questions/2506077/how-to-read-integer-value-from-the-standard-input-in-java